If it's not what You are looking for type in the equation solver your own equation and let us solve it.
5x^2-25x+4=0
a = 5; b = -25; c = +4;
Δ = b2-4ac
Δ = -252-4·5·4
Δ = 545
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-25)-\sqrt{545}}{2*5}=\frac{25-\sqrt{545}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-25)+\sqrt{545}}{2*5}=\frac{25+\sqrt{545}}{10} $
| 3x-32=90 | | -7n-3(7n-3)=177 | | V+1/v-7+1=v-7/v-4 | | 3x-46=90 | | -6(-6k-5)-2k=-106 | | x-46=90 | | 4(-4+8n)=-272 | | 82=2(1+5p) | | -3.9u=7.75 | | 4(3x+4)=2x | | 0,5x=-35 | | 287=7(7x-1) | | -6x+7=30 | | (4(x+5)=28) | | 9+x+5x=2-5x+5x | | 4/5+4x=5x-6/5 | | 5x=1x+9 | | -174=5(1+6n)+1 | | 5*(x+3)=2x*(x+3) | | 38=3x-16 | | 6x-11x+8(-2x-4)+2(x+2)=-4(3x+3) | | 3(8-2x)=-6 | | 3.8=-2p+5.8 | | 9+x=2-5x+5x | | 6(10+3x)-24=3(5x+2) | | 2+6x=6+3x-3x | | 4(2y+11=2(y-13) | | 4x^2-6x+7=0 | | 24=4+2x | | 4y-6=8-3y | | x+11/2=-40 | | 6/5+4n=4/5-5n |